Trigonometrical Identities
1. Quotient relations:
- tan
= sin
/cos 
- cot
= cos
/sin 
2. Reciprocal relations:
- sin
= 1/ cosec 
- cosec
= 1/sin 
- cos
= 1/sec 
- sec
= 1/cos 
- tan
= 1/cot 
- cot
= 1/tan 
3. Square relations (Fundamental Identities):
- sin²
+cos²
= 1
- 1 +tan²
= sec² 
- 1 +cot²
= cosec² 
4. T-ratios of standard angles:
| |
0° |
30° |
45° |
60° |
90° |
| Sin |
 |
 |
 |
 |
 |
| Cos |
 |
 |
 |
 |
 |
5. T-ratios of complementary angles:
- sin (90° -
) = cos 
- cos (90° -
) = sin 
- tan (90° -
) = cot 
- cot (90° -
) = tan 
- sec (90° -
) = cosec 
- cosec (90° -
) = sec 
Exercise
Prove the following identities (1 -15):
- tan²
- 1/cos²
+1 = 0
- sin A/(1 +cosA) +(1 +cos A)/sin A = 2 cosecA
- (1 -sin
)/(1 +sin
)
= (sec
-tan
)²
- sec² A +cosec² A = sec² A cosec²A
- sec4
-tan4
= 1 +2 tan² 
- tan² A/(1+tan² A) + cot² A/(1 +cot² A) = 1
- (1 -cos
)(1 +sec
)
= tan
sin 
- (cot² A -tan² A)/(cot A +tan A)² = 2 cos² A -1
- cos4
+sin4
+2 sin²
cos²
= 1
= cosec
+cot 
.
- sec
(1 -sin
)(sec
+tan
) =1
- (sec A +cos A)(sec A -cos A) = tan²A +sin² A
- tan²
-sin²
= tan²
sin² 
- (1 -cos
)(1 + cos
)(1 +cot²
) = 1
Simplify the expression in questions (16 -27):
- (sin² A -cos² A)/(sin A -cos A)
- sin²
cos
cosec³
sec 
- cot B sin² B cot B
- (cos² A +cos A -12)/cos A - 3)
- tan
/(sec
-1)
+ tan
/(sec
+1)
- sec A csc A -tan A -cot A
- (cot²
+tan²
)/(cos²
sec²
)
- x = a sec
, y = b tan 
- x = h +a cos
, y = k
+b sin 
- x = a sec³
, y = b tan³

- tan
+sin
= m, tan
- sin
= n
- cot
+cos
= m, cot
-cos
= n
When 0° <
< 90°, solve the following equations (28-33):
- 2 sin²
= 1/2
- 4 cos²
-3 = 0
- sin²
-(1/2)sin
= 0
- tan²
= 3 (sec
-1)
- 2 cosec
= 3 sec² 
- 3 tan
+cot
= 5 cosec 
Without using trigonometric tables, evaluate (34-43):
- (cos0° +sin45° +sin30°).(sin90° -cos45° +cos60°)
- sin² 45° -tan² 60° + cos² 90°
- sin 23°/cos 67°
- cosec 31°/ sec 59°
- sin² 38° -sin²52°
- sin 18° -cos 72°
- sin 36° sec 54° +cos 24° cosec 66°
-
.
- cosec²67° -tan² 23°
- sec 31° sin 59° +cos 31° cosec 59°
Express the following in terms of t-ratios of angles between 0° and 45°.
- sin 85° +cosec 85°
- cosec 69° +cot 69°
- sin 81° +tan 81°
- cos 56° +cot 56°
Prove the following:
- [sin (90 -A) sin A]/tan A-1 = - sin² A
- cos
cos(90° -
) -sin
sin (90° -
) = 0
- sin (90° -
) cos (90° -
)
= tan
/(1 +tan²
)
- cosec² (90° -
) -tan²
= cos²(90° -
) +cot² 
- If cos
/cos
= m and
cos
/sin
= n, show that (m²
+n²) cos²
= n².
- If x = r cos
sin
,
y = r cos
cos
and z
= r sin
, show that x² +y² +z²
= r².
Answers
16. sin A +cos A
17. csc
18. cos² B
19. cos A +4
20. 2 csc
21. 0
22. 1
23. x²/a² - y²/b² = 1
24.
25. 
26. (m² -n²)² = 16 mn
27. (m² -n²)² = 16 mn
28. 30°
29. 30°
30. 30°
31. 60°
32. 30°
33. 60°
34. -5/2
35. 1
36. 1
37. 1
38. 0
39. 2
40. 1/2
41. 1
42. 2
43. 0
44. sec 21° +tan 21°
45. cos 9° +cot 9°
46. sin 34° +tan 34°
47. sin²