The point which divides a median of a triangle in the ratio 2 : 1 is called
the centroid of the triangle. Thus, if AD is a median of the triangle ABC and
G is its centroid, then
AG/GD = 2/1

By section formula, the co-ordinates of G are

The symmetry of the co-ordinates of G shows that it also lies on the medians
through B and C. Hence the medians of a triangle are concurrent.
Incenter of a triangle
The point of the intersection of any two internal bisectors of the angles
of a triangle is called the incenter of the triangle. It is usually denoted by I.

If the internal bisector of
A of a
ABC meets the side BC in D, then
BD/DC = AB/AC
By section formula, the co-ordinates of I are
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The symmetry of the co-ordinates of I shows that it also lies on the internal
bisector of
C.
Hence the internal bisectors of the angles of a triangle are concurrent.
Find the co-ordinates of the incenter of the triangle whose vertices are(-2,4), (5,5) and (4,-2).
Let A (-2,4), B (5,5) and C (4,-2) be the vertices of the given triangle ABC, then
a = | BC| =
[(4 -5)² +(-2 -5)²] =
[1
+49] =
50 = 5
2,
b = |CA| =
[(4 -2)² +(-2 -4)²] =
[36
+36] =
72 = 6
2 and
c = |AB| =
[(5 -2)² +(5 -4)²] =
[49
+1] =
50 = 5
2.
The co-ordinates of the incenter of
ABC are
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