Show that cos 10° +cos 110° +cos 130° = 0
cos 10° +cos 110° +cos 130° = (cos 110° +cos 10°) +cos 130°
= 2 cos (110° +10°)/2 cos (110° -10°)/2 +cos (180° -50°)
= 2 cos 60° cos 50° -cos 50° = 2.(1/2) cos 50° -cos 50° = 0
Prove that cos 20° cos 40° cos 80° = 1/8
cos 20° cos 40° cos 80° = (1/2) cos 40° (2 cos 80° cos 20°)
= (1/2) cos 40° (cos (80° +20°) + cos (80° -20°))
= (1/2) cos 40° (cos 100° + cos 60°) = 1/2 cos 40° (cos 100° +1/2)
= (1/4) cos 40° +(1/4) (2 cos 100° cos 40°)
= (1/4) cos 40° + (1/4) (cos 140° +cos 60°)
= (1/4) cos 40° - (1/4)cos 40° +(1/4)(1/2)
(Since cos 140° = cos (180° -40°) = -cos 40°)
= 1/8